Question 952934: Four cars-A, B, C, and D- are in a drag race. A, B, C have the same probability of winning and each is three times as likely to win as D. Find each car's probability of winning.
I have tried using the complement rule - P(E') = 1 - P(E) and I got 3/4 but I'm solving this clueless. I don't even know if this attempt is remotely close to the correct answer. Please help
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Four cars-A, B, C, and D- are in a drag race. A, B, C have the same probability of winning and each is three times as likely to win as D. Find each car's probability of winning.
I have tried using the complement rule - P(E') = 1 - P(E) and I got 3/4 but I'm solving this clueless. I don't even know if this attempt is remotely close to the correct answer. Please help
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Probability D wins :: x
Probability A wins :: 3x
B wins................3x
C wins................3x
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Equation:
Sum of probabilities = 1
x + 3x + 3x + 3x = 1
10x = 1
x = 1/10 (prob D wins)
3x = 3/10 (prob each of A, B, C wins)
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Cheers,
Stan H.
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