Question 952747: All applicants for a job in X-Company should take a test. To be invited for an interview your score on the test should be on the top 10% percent of all applicants. Results of the test have Normal Distribution with the mean 340 and Standard Deviation 85. Take values 340, 85 and 10% assigned for you in the table below and find, what should be your score on the test (higher than what value ?) to be invited for the interview.
Take values 340, 85 and 10%. From Appendix Table for Normal Distribution find z-value that has area to the left close to
1-10% (10% should be in decimal form).
2. In formula z=(x-340)/85 to plug your z, 340 and 85 and solve for x.
That will be score on the test required to be invited for the interview.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! All applicants for a job in X-Company should take a test. To be invited for an interview your score on the test should be on the top 10% percent of all applicants. Results of the test have Normal Distribution with the mean 340 and Standard Deviation 85. Take values 340, 85 and 10% assigned for you in the table below and find, what should be your score on the test (higher than what value ?) to be invited for the interview.
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I used a TI-84+ calculator.
Find the z-value with a left tail of 0.90:: invNorm(0.9) = 1.2816
Find the corresponding score using:: x = z*s+u
x = 1.2816*85+340
x = 448.93
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Ans: Minimum score to be invited:: 449
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Cheers,
Stan H.
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