SOLUTION: I'm in a weekly confidence office football pool (60 participants) and am curious to know what is the probability of one participant winning three out of six weeks with all other th
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Question 922372: I'm in a weekly confidence office football pool (60 participants) and am curious to know what is the probability of one participant winning three out of six weeks with all other things considered equal. Thanks, Tim Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I'm in a weekly confidence office football pool (60 participants) and am curious to know what is the probability of one participant winning three out of six weeks with all other things considered equal.
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If all other things are equal (and they really are not) the probability
you are looking for is 6C3(1/60)^3*(59/60)^3 = 0.000088
or 88 out of 1 million.
Cheers,
Stan H.
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