SOLUTION: ) The table below shows the numbers of two- to five-bedroom houses in the Belmont neighborhood. Number of Bedrooms Frequency 2 12 3 4

Algebra ->  Probability-and-statistics -> SOLUTION: ) The table below shows the numbers of two- to five-bedroom houses in the Belmont neighborhood. Number of Bedrooms Frequency 2 12 3 4      Log On


   



Question 871914: )

The table below shows the numbers of two- to five-bedroom houses in the Belmont neighborhood.
Number of Bedrooms Frequency
2 12
3 40
4 70
5 3
What is the probability that a randomly selected house will have 3 or fewer bedrooms?

A)

0.560

B)

0.416

C)

0.320

D)

0.584

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Number of Bedrooms Frequency
2 12
3 40
4 70
5 3


There are 12+40+70+3 = 125 homes being surveyed.

"3 or fewer" means "at most 3" (think of it as the ceiling or as high as you can go). X = 2 is the lowest you can go on the table while X = 3 is the highest we want. So we just need to calculate P(X = 2) and P(X = 3) then add up them. The variable X is defined as X = number of bedrooms.


From the table, we get the following probabilities

P(X = 2) = 12/125
P(X = 3) = 40/125

Use them to calculate P(X <= 3)

P(X <= 3) = P(X = 2) + P(X = 3)
P(X <= 3) = 12/125 + 40/125
P(X <= 3) = (12 + 40)/125
P(X <= 3) = 52/125
P(X <= 3) = 0.416


So the final answer is 0.416