SOLUTION: A box contains 278 red marbles and 45 yellow marbles. If you draw one marble at random, what is the probability, to the nearest percent, that it is yellow

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Question 733215: A box contains 278 red marbles and 45 yellow marbles. If you draw one marble at random, what is the probability, to the nearest percent, that it is yellow
Found 2 solutions by lynnlo, ikleyn:
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
1/323% chance

Answer by ikleyn(53763) About Me  (Show Source):
You can put this solution on YOUR website!
.
A box contains 278 red marbles and 45 yellow marbles. If you draw one marble at random,
what is the probability, to the nearest percent, that it is yellow
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The rational and the decimal expressions for the probability are  

    P = 45%2F%28278%2B45%29 = 45%2F323 = 0.13932  (rounded).


In the percentage form, it is  13.932%.


To the nearest percent this is 14%.

Solved.

The answer in the post by @lynnlo is incorrect.