SOLUTION: If 2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, and, What is 7+8 = ?

Algebra ->  Probability-and-statistics -> SOLUTION: If 2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, and, What is 7+8 = ?      Log On


   

Question 670816: If 2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, and, What is 7+8 = ?
Found 2 solutions by MathLover1, swincher4391:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


2%2A1+%2B+3%2A2+=+8
3%2A2+%2B+7%2A3+=+27
4%2A3+%2B+5%2A4+=+32
5%2A4+%2B+8%2A5+=+60
6%2A5+%2B+7%2A6+=+72
7%2A6+%2B+8%2A7+=+98....your answer

Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Wow, this problem is crazy. So notice this:

2+3-1 = 5 -1 = 4 *2 = 8
3+7-1 = 10-1 = 9 *3 = 27
4+5-1 = 9-1 = 8 * 4 = 32
5+8-1 = 13-1 = 12 * 5 = 60
6+7-1 = 13-1 = 12 *6 = 72
7+8-1 = 15-1 = 14*7 = highlight%2898%29
So we subtract 1 and then we multiply by the first number.