SOLUTION: please help check and explain! Dealt 6 cards from a 52 card deck A. Probability you are dealt no spades and exactly 2 sevens? I tried (3C2)(39C4/52C4=246753/270725=.9115

Algebra ->  Probability-and-statistics -> SOLUTION: please help check and explain! Dealt 6 cards from a 52 card deck A. Probability you are dealt no spades and exactly 2 sevens? I tried (3C2)(39C4/52C4=246753/270725=.9115       Log On


   

Question 635808: please help check and explain!
Dealt 6 cards from a 52 card deck
A. Probability you are dealt no spades and exactly 2 sevens?
I tried (3C2)(39C4/52C4=246753/270725=.9115
B. Probability that you are dealt no more than 1 jack?
I came up with..
(48C6)+(4C1)(48C5)/52C6=.9392
C. Probability that you are deal at least 2 hearts and at least 2 clubs?
I am really struggling with this one..I think its something along the lines of
(4C2*4C2*44C2)+(4C3*4C3*44C2)/52C6
Any help would be awesome.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Dealt 6 cards from a 52 card deck  52C6 TOTAL possibilities

P(no spades 'and' 2 7s) = 3C2%2A36C4%2F%2852C6%29

P(1Jack and 5 non-jack cards) = 4C1%2A48C5%2F%2852C6%29

P(no Jacks) = 48C6%2F%2852C6%29

P(no more than one Jack) = %2848C6+%2B+4C1%2A48C5%29%2F%2852C6%29

P(least 2 Hs and 2 Cs) = 1 - %2826C6+%2B+13C1%2A13C1%2A26C4%29%2F%2852C6%29