SOLUTION: Eight people, all of different heights, are to be seated in a row. Neither the tallest person nor the shortest person is seated at either end of the row.
a.) how many different
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-> SOLUTION: Eight people, all of different heights, are to be seated in a row. Neither the tallest person nor the shortest person is seated at either end of the row.
a.) how many different
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Question 629234: Eight people, all of different heights, are to be seated in a row. Neither the tallest person nor the shortest person is seated at either end of the row.
a.) how many different seating arrangements are possible?
b.) what is the probability that the tallest and shortest people are sitting next to each other? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Eight people, all of different heights, are to be seated in a row. Neither the tallest person nor the shortest person is seated at either end of the row.
a.) how many different seating arrangements are possible?
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# of ways to succeed:
1st position: 6 ways
8th position: 5 ways
2nd thru 7th positions: 6! ways
Total ways: 30*6! = 21600
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b.) what is the probability that the tallest and shortest people are sitting next to each other?
# of ways to succeed:
1st position: 6 ways
8th position: 5 ways
2nd thru 7th positions: 2*5! = 240 (treat the 2 persons as one)
Ans: Probability = (6*5*240)/21600 = 1/3
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Cheers,
Stan H.
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