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put this solution on YOUR website! In a drawing of six numbers using the same balls numbered 0 to 9, what are the
odds that the same number will be drawn twice?
The number of failures is the number of permutations of 9 things taken 6 at a
time, or P(9,6) = 9·8·7·6·5·4 = 60480
The number of possible sequences of 6 is 9·9·9·9·9·9 = 96
The number of successes is 96 - P(9,6) = 531441 - 60480 = 470961
So The odds in favor = (number of successes):(number of failures) =
470961:60480
which reduces to
17443:2240
or about 7.8 to 1
Edwin