SOLUTION: how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?

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Question 581303: how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?
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Ans: 9C2*5C1*4C1 = 36*5*4 = 720
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Cheers,
Stan H.
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