Question 580970: Hi there, PLease help :)
What would have to be the test score (rounded to once place to the right of a decimal) to qualify for admittance into a institution with a mean of normally distributed test scores of 82.5 and a standard deviation was 6.9, assuming admittance depended on being in the top 17 percent.
Thanks,
Fiona
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What would have to be the test score (rounded to once place to the right of a decimal) to qualify for admittance into a institution with a mean of normally distributed test scores of 82.5 and a standard deviation was 6.9, assuming admittance depended on being in the top 17 percent.
----
Find the z-score with a left tail of 0.83
invNorm(0.83) = 0.9542
----
That tells you the score you are looking for is 0.9542
standard deviations above the mean.
----
Find that score:
x = 0.9542*6.9+82.5 = 89.08
===============================
Cheers,
Stan H.
===============
|
|
|
