SOLUTION:
Given a normal distribution of values for which the mean is 140 and the
standard deviation is 33, nd the 90th percentile for this distribution.
Round your answers to 3 decimal
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Given a normal distribution of values for which the mean is 140 and the
standard deviation is 33, nd the 90th percentile for this distribution.
Round your answers to 3 decimal
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Question 540986:
Given a normal distribution of values for which the mean is 140 and the
standard deviation is 33, nd the 90th percentile for this distribution.
Round your answers to 3 decimal places. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Given a normal distribution of values for which the mean is 140 and the
standard deviation is 33, find the 90th percentile for this distribution.
Round your answers to 3 decimal places.
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Find the z-value with a left tail of 90%
invNorm(0.90) = 1.2816
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90th %ile score = z*s + u = 1.2816*33 + 140 = 182.291
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Cheers,
Stan H.
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