Question 471555: There are 50,000 people at a stadium watching a soccer match, and 40,000 of them are male. If 3 people are chosen at random, what is the probability that all 3 of them are male?
Found 2 solutions by poliphob3.14, ewatrrr:
Answer by poliphob3.14(115)   (Show Source):
You can put this solution on YOUR website! n(S)=C(50000, 3) and n(A)=C(40000, 3)
The p(A), probability that 3 people chosen to be male is:P(A)=n(A)/n(S)
P(A)=C(40000, 3)/C(50000, 3)=0.512.
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi,
Note: The probability of x successes in n trials is:
P = nCx*  where p and q are the probabilities of success and failure respectively.
In this case p(male)= 40,000/50,000 = = .8 and q(female) = .2
nCx = 
3 chosen
P(3 males) = (.8)^3 = .512
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