SOLUTION: A jar contains three green marbles and five white marbles. Suppose you choose a marble at random, and do not replace it. Then you choose a second marble. Find the probability of ea

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Question 437437: A jar contains three green marbles and five white marbles. Suppose you choose a marble at random, and do not replace it. Then you choose a second marble. Find the probability of each event.
If I select a green marble then a white marble, what would be the correct probability?
Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
3+5=8
.
3/8 * 5/7 = 15/56 Probability of drawing a green and then a white without replacement.
.
Ed

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A jar contains three green marbles and five white marbles. Suppose you choose a marble at random, and do not replace it. Then you choose a second marble. Find the probability of each event.
If I select a green marble then a white marble, what would be the correct probability?
P(green then white without replacement) = (3/8)(5/7) = 15/56
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Cheers,
Stan H.
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