Question 417624: A recent study of cardiovascular risk factors reports that 30% of adults meet the criteria for hypertension. If 15 adults are assessed, what is the probability that:
a. Exactly 15 meet the criteria for hypertension?
b. None meet the criteria for hypertension?
c. Less than or equal to 7 meet the criteria for hypertension?
Diastolic blood pressures are assumed to follow a normal distribution with a mean of 85 and a standard deviation of 12.
a. What proportion of people have diastolic blood pressures less that 90?
b. What proportions have diastolic blood pressures between 80 and 90?
c. If someone has a diastolic blood pressure of 100, what percentile does this represent?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A recent study of cardiovascular risk factors reports that 30% of adults meet the criteria for hypertension. If 15 adults are assessed, what is the probability that:
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Binomial Problem with n=15 and p = 0.3
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a. Exactly 15 meet the criteria for hypertension?:::0.3^15
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b. None meet the criteria for hypertension?::0.7^15
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c. Less than or equal to 7 meet the criteria for hypertension?
binomcdf(15,0.3,7) = 0.9500
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Diastolic blood pressures are assumed to follow a normal distribution with a mean of 85 and a standard deviation of 12.
a. What proportion of people have diastolic blood pressures less that 90?
z(90) = (90-85)/12 = 0.4167
P(x<90) = P(z<0.4167) = normalcdf(-100,0.4167) = 0.6616
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b. What proportions have diastolic blood pressures between 80 and 90?
Find the z-values and find the proportion between them.
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c. If someone has a diastolic blood pressure of 100, what percentile does this represent?
On a normal distribution the probability of any particular value is zero.
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Cheers,
Stan H.
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