Question 416881: What is the probability of not getting a 9 on two dice?
Found 2 solutions by sudhanshu_kmr, ewatrrr:
Answer by sudhanshu_kmr(1152)   (Show Source):
You can put this solution on YOUR website!
possible case for getting 9 is (4,5), (5,4),(6,3) ,(3,6)
probability of getting 9, i.e P(A) = 2/36
probability of not getting 9, i.e P'(A) = 1 - P(A) = 1 - 2/36 = 34/36
= 17/18
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi
P(not getting a 9) = 1 - P(9) = 1 - 4/36 = 32/36 = 8/9
___1_2_3__4__5__6
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_7__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12
|
|
|
