SOLUTION: A foreman at a large plant estimates defective parts about 1% of the time. If the plant produces 30,000 parts in a week, what is the standard deviation (to the nearest tenth) for t

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Question 364399: A foreman at a large plant estimates defective parts about 1% of the time. If the plant produces 30,000 parts in a week, what is the standard deviation (to the nearest tenth) for the number of defective parts?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
This is a binomial experiment with n = 30000, p = 0.01, and q = 1-p = 0.99. The mean is mu+=+300 and the standard deviation is sigma+=+sqrt%28npq%29+=+sqrt%2830000%2A0.01%2A0.99%29+=+17.2337, to 4 decimal places.