SOLUTION: The amount of work-hours involved in the festival preparation by company employees is normally distributed around 150 hours with a standard deviation of 20 hours.
What’s the p
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What’s the p
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Question 364040: The amount of work-hours involved in the festival preparation by company employees is normally distributed around 150 hours with a standard deviation of 20 hours.
What’s the probability that the mean number of work-hours will be between 160 and 190?
I tried this but I was told it was wrong. Is there something I did wrong or is it all completely wrong?
Z1= (160 - 150)/20 = 5. = .1915
Z2 = (190 – 150)/20 = 2 = .4772
ANSWER: .1915 + .4772 = .6687 = 66.87%
P(160< X <190)
Z1= (160 - 150)/20 = 0.5 = .1915
Z2 = (190 – 150)/20 = 2 = .4772
required probability should be
P(z2)- P (z1)
=0.4772 - 0.1915
=0.2857
here is a graph that I did in minitab for your viewing pleasure. :)
Copy and paste the link below in your browser.
http://yfrog.com/j4sadiekhanstatsj
Hope that helps
Sadiekhan
www.tinyurl.com/sadiestats
