SOLUTION: A state weights-and-measures standard requires that no more than 5 percent of bags of Halloween candy be underweight.A random sample of 200 bags showed that 16 were underweight. (a

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Question 293128: A state weights-and-measures standard requires that no more than 5 percent of bags of Halloween candy be underweight.A random sample of 200 bags showed that 16 were underweight. (a) At α = .025, is the standard being violated? Use a right-tailed test and showyourwork. (b) Find the p-value.
Answer by stanbon(75887) About Me  (Show Source):
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A state weights-and-measures standard requires that no more than 5 percent of bags of Halloween candy be underweight.A random sample of 200 bags showed that 16 were underweight. (a) At α = .025, is the standard being violated? Use a right-tailed test and showyourwork. (b) Find the p-value.
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Ho: p = 0.05
Ha: p > 0.05
test statistic: z(16/200) = (0.08-0.05)/sqrt(0.05*0.95/200) = 1.9467
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p-value = P(z > 1.9467) = 0.0258
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Since the p-value is greater than alpha, fail to reject Ho.
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Cheers,
Stan H.