SOLUTION: Hi, can anyone help me here. Can you show me the steps. Thanks in advance
A sample of 40 CDs from a student’s collection showed a mean length of 52.74 minutes with a standard de
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A sample of 40 CDs from a student’s collection showed a mean length of 52.74 minutes with a standard de
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Question 293125: Hi, can anyone help me here. Can you show me the steps. Thanks in advance
A sample of 40 CDs from a student’s collection showed a mean length of 52.74 minutes with a standard deviation of 13.21 minutes. Construct a 95 percent confidence interval for the population standard deviation. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A sample of 40 CDs from a student’s collection showed a mean length of 52.74 minutes with a standard deviation of 13.21 minutes. Construct a 95 percent confidence interval for the population standard deviation.
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Sample std = 13.21; Sample variance = 174.50
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df=39
lower Chi-Sq: 23.65 for df=39 and alpha/2 = 0.025
upper Chi-Sq: 58.12 for df=39 and alpha/2 = 0.025
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95% Confidence Interval:
[(39)(174.50)]/58.12 < s^2 < [(39)(174.50)]/23.65
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117.09 < s^2 < 287.76
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10.82 < s < 16.96
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Cheers,
Stan H.
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