SOLUTION: If three fair dice are tossed and the product of the numbers that appear is even, what is the probability that the sum of the numbers is also even?
a 2/5 b 3/5 c 4/7 d
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-> SOLUTION: If three fair dice are tossed and the product of the numbers that appear is even, what is the probability that the sum of the numbers is also even?
a 2/5 b 3/5 c 4/7 d
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Question 252358: If three fair dice are tossed and the product of the numbers that appear is even, what is the probability that the sum of the numbers is also even?
a 2/5 b 3/5 c 4/7 d 5/7 e 7/9 Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! What the question wants is P (the sum is even, given the product is even). The formula for this is
P(sum even AND product even) / P(product even)
we toss three times, which means 8 total possible outcomes. Of those 8, the product is even 7 times and the sum is even 4 times. You can easily create a table for these.
(i) the product AND sum are even 4 times
(ii) the product is even by itself 7 times.
We have (4/8) / (7/8) = 4/7 which appears to be choice [ C ].
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