SOLUTION: Find P(A or B or C) for the given probabilities. P(A=0.39, P(B)=0.27,P(c)=0.18 P(A and B)=0.13,P(A and C)=0.03,P(B and C)=0.09 P(A and B and C)=0.01 P(A or B or C)=

Algebra ->  Probability-and-statistics -> SOLUTION: Find P(A or B or C) for the given probabilities. P(A=0.39, P(B)=0.27,P(c)=0.18 P(A and B)=0.13,P(A and C)=0.03,P(B and C)=0.09 P(A and B and C)=0.01 P(A or B or C)=      Log On


   

Question 189546: Find P(A or B or C) for the given probabilities.
P(A=0.39, P(B)=0.27,P(c)=0.18
P(A and B)=0.13,P(A and C)=0.03,P(B and C)=0.09
P(A and B and C)=0.01
P(A or B or C)=
Answer by kev82(151) About Me  (Show Source):
You can put this solution on YOUR website!
Let Q = A or B
P(A or B or C) = P(Q or C) = P(Q) + P(C) - P(Q and C)
P(Q) = P(A) + P(B) - P(A and B)
P(Q and C) = P((A and C) or (B and C)) = P(A and C) + P(B and C) - P(A and B and C)
P(A or B or C) = P(A)+P(B)-P(A and B)+P(C)-(P(A and C) + P(B and C) - P(A and B and C))
P(A or B or C) = P(A)+P(B)+P(C)-P(A and B)-P(A and C)-P(B and C)+P(A and B and C)
P(A or B or C) = 0.39+0.27+0.18-0.13-0.03-0.09+0.01 = 0.6