SOLUTION: For 10 observations on price (X) and supply (Y) the following data were obtained (in appropriate units): ∑X = 130, ∑Y = 220, ∑X 2 = 2288, ∑Y 2 = 5506 and ∑XY = 34

Algebra ->  Probability-and-statistics -> SOLUTION: For 10 observations on price (X) and supply (Y) the following data were obtained (in appropriate units): ∑X = 130, ∑Y = 220, ∑X 2 = 2288, ∑Y 2 = 5506 and ∑XY = 34      Log On


   



Question 1188967: For 10 observations on price (X) and supply (Y) the following data were
obtained (in appropriate units):
∑X = 130, ∑Y = 220, ∑X
2 = 2288, ∑Y
2 = 5506 and ∑XY = 3467.
Obtain the line of regression of Y on X and estimate the supply when the price is 16
units, and find out the standard error of the estimate.

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i will attempt to answer most of this, if not all.

you are given:

sum(x) = 130
sum(y) = 220
sum(x^2) = 2288
sum(y^2) = 5506
sum(xy) = 3467

the regression equation is y = a + b * x

there are formulas to derive a and b.

they are:

a = (sum(y)*sum(x^2)-sum(x)*sum(xy))/(n*sum(x^2)-sum(x)^2)

b = (n*sum(xy)-sum(x)*sum(y))/(n*sum(x^2)-sum(x)^2)

n is the number of (x,y) data points in the data set.

your solution is that the line of regression is equal to:

y = 8.804347826 + 1.015050167 * x

when x is equal to 16, y is equal to 25.0451505.

here's a reference on the formulas used to get y = a + b * x regression equation.

https://byjus.com/maths/linear-regression/

i had some difficulty understanding how to derive the standard error.
i will look at that again to see if it can be derived from the data presented.
i will do that by tomorrow morning or the next morning after that.
stay tuned.

please send reply with your email so i can let you know when i have the answer.
just a reply through algebra.com should be enough.

theo