SOLUTION: Let P(A) = 0.39, P(B) = 0.14, and P(A ∩ B) = 0.06. a. Calculate P(A | B). (Round your answer to 2 decimal places.) b. Calculate P(A U B). (Round your answer to 2 decima

Algebra ->  Probability-and-statistics -> SOLUTION: Let P(A) = 0.39, P(B) = 0.14, and P(A ∩ B) = 0.06. a. Calculate P(A | B). (Round your answer to 2 decimal places.) b. Calculate P(A U B). (Round your answer to 2 decima      Log On


   

Question 1162633: Let P(A) = 0.39, P(B) = 0.14, and P(A ∩ B) = 0.06.
a. Calculate P(A | B). (Round your answer to 2 decimal places.)

b. Calculate P(A U B). (Round your answer to 2 decimal places.)

c. Calculate P((A U B)c). (Round your answer to 2 decimal places.)
P((A U B)c)
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

(a)  P(A|B) = by the definition of conditional probability = P(A ∩ B) / P(B) = 0.06%2F0.39.  Use your calculator.



(b)  P(A U B) = P(A) + P(B) - P(A ∩  B) = 0.39 + 0.14 - 0.06.    Use your calculator.




(c)  P((A U B)c)  is the complement to the value of P(A U B) from (b).

Solved.