.
Read attentively on how I re-formulated your original post to make sense.
in how many distinct ways can a
5-symbol password be made using
two letters and three
digits if no repeats are allowed?
Solution
You have 5 symbols : 5 = 2 letters + 3 digits,
so 5! = 120 permutations are possible. ANSWER
/\/\/\/\/\/\/\/
Two different readings and interpretations of your condition are possible.
1. Two fixed letters and 3 fixed digits are allowed / (are used).
It is exactly that reading and interpretation that I used in my solution.
and
2. Any two letters of the English alphabet and any 3 digits of ten digits are allowed.
Then the solution should be different.
But just the fact that two different interpretations are possible makes this formulation DEFECTIVE.