Question 1134124: Given two events A and B such that P(A) = 0.67, P(B)= 0.23 and P (A /intersection/ and B) = 0.12, find each probability.
A. P(A')
B. P(B')
C. P(A U B)
D. P(A U B)'
Answer by ikleyn(52816)   (Show Source):
You can put this solution on YOUR website! .
Given two events A and B such that P(A) = 0.67, P(B)= 0.23 and P (A /intersection/ and B) = 0.12, find each probability.
A. P(A') = 1 - P(A) = 1 - 0.67 = 0.33.
B. P(B') = 1 - P(B) = 1 - 0.23 = 0.77.
C. P(A U B) = P(A) + P(B) - P(A intersection B) = 0.67 + 0.23 - 0.12 = 0.78. <<<---=== it is VERY important formula,
and those who know it, have a huge advantage comparing with those who do not know (!)
D. P(A U B)' = 1 - P(A U B) = 1 - 0.78 = 0.22.
Solved. // All questions are answered.
|
|
|
