Question 1128415: A bird breeder has a total of 50 canaries, 21 are male and 29 are female. a pet shop randomly selects 8 of them.
1. probability that none of the eight are female?
2. probability that five of the eight are male?
3. probability that at least 6 of the 8 are female?
4. probability that at least two of the eight are males?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The number of ways to choose 8 is 50C8 or 536878650
21C8 are the number of ways to choose 8 males, so 1. probability is 0.000379 or 0.0004
2. five of eight male, 3 female has a numerator of 21C5*29C3, and probability is 0.1385
3. This would be 21C2*29C6 for the numerator, and probability is 0.1858.
4. Look at probability of 1 a male and 0 a male and subtract that sum from 1.
21C1*29C7/50C8=0.0610 and 21C0*29C8/50C8=0.008, sum is 0.1410 and the overall probability of at least 2 males is 0.8590
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