SOLUTION: A box contains two blue, three red and five white balls of equal sizes. Two balls are picked at random, the first being replaced before the second is drawn. Find the probability of
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Question 1118706: A box contains two blue, three red and five white balls of equal sizes. Two balls are picked at random, the first being replaced before the second is drawn. Find the probability of drawing
a.) a red or a blue ball first
b.) two red balls
c.) two blue balls
d.) two balls of the same colour. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! There are 10 balls drawn with replacement
red first is 3/10 and blue first is 2/10, so the probability is 0.5 that one of the two is drawn first.
two red balls would be (3/10)(3/10)=9/100
two blue balls would be (2/10)(2/10)=4/100 or 1/25
two balls of the same color would include two white balls (5/10)(5/10)=1/4
The sum of the three is 9/100+4/100+25/100 or 38/100 or 0.38, the probability both balls are the same color.
