SOLUTION: Three cards are drawn and not replaced from a standard deck. What is the probability that all three cards will be from different suits?

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Question 1118274: Three cards are drawn and not replaced from a standard deck. What is the probability that all three cards will be from different suits?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st card is guaranteed to be one of
the 4 suits and you don't care which suit
it is, so the probability is +1
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There are now +51+ cards left. There are
+52+-+13+=+39+ cards of other suits, so the P
of getting a different suit is: +39%2F51+
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Now there are +50+ cards left, and 2 of the
suits have been eliminated. There are
+52+-+26+=+26+ cards to choose from, so
the P of getting a different suit is:
+26%2F50+
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P( 3 different suits ) = +1%2A%2839%2F51%29%2A%2826%2F50%29+
+%28+39%2A26+%29+%2F+%28+51%2A50+%29+
+1014+%2F+2550+=+.39765+
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