First we calculate how many indistinguishable
permutations of the 16 letters:
A,D,D,E,I,L,L,M,M,O,O,O,R,R,T,V
If the letters were distinguishable the
answer would be 16!
However there are:
2 indistinguishable D's,
2 indistinguishable L's,
2 indistinguishable M's,
3 indistinguishable O's,
2 indistinguishable R's.
So we must divide the 16! by 2!2!2!3!2!
That works out to be 217945728000.
So the probability is 1 way out of 217945728000 or
Edwin