Let x,y,z, and w be the probabilities of the 4 regions
in the Venn diagram below:
P(A) = x+y = 0.3
P(B) = y+z = 0.6
P(A&B') = x = 0.1
P(AUB) = x+y+z = ??
Since x = 0.1,
substitute 0.1 for x in x+y = 0.3
0.1+y = 0.3
y = 0.2
Substitute 0.2 for y in y+z = 0.6
0.2+z = 0.6
z = 0.4
P(AUB) = x+y+z = 0.1+0.2+0.4 = 0.7 <--answer
It's also true that w = P(A'&B') = 1 - 0.7 = 0.3
Edwin