Question 1072890: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event A: The sum is greater than 9 .
Event B: The sum is not divisible by 5.
Write your answers as exact fractions.
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! Look at the possible outcomes, there are 36 of them starting with (1,1) and going to (6,6). The sums range from 2 to 12 with the following distribution,
2,1
3,2
4,3
5,4
6,5
7,6
8,5
9,4
10,3
11,2
12,1
So the number of outcomes greater than 9 is 
Only the sum of 5 is divisible by 5, it occurs twice.  so then  of the outcomes are not divisible by 5.
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