SOLUTION: a box contains 4 red balls and 8 white balls. how much greater is the probability of simultaneously drawing 2 white balls at random than simultaneously drawing 2 red balls at rando
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Question 1043746: a box contains 4 red balls and 8 white balls. how much greater is the probability of simultaneously drawing 2 white balls at random than simultaneously drawing 2 red balls at random? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Two white balls at random without replacement is (8/12)*(7/11)=56/132, or 14/33.
Two red balls at random without replacement is (1/3)(3/11)=1/11
The difference (the amount greater) is 14/33-3/33=11/33, or 1/3.
