SOLUTION: Suppose the chance of rain for each of the next three days is 50%, You are planning an outdoor activity and want to estimate the chance that it will not rain at least one of the da
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-> SOLUTION: Suppose the chance of rain for each of the next three days is 50%, You are planning an outdoor activity and want to estimate the chance that it will not rain at least one of the da
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Question 1039820: Suppose the chance of rain for each of the next three days is 50%, You are planning an outdoor activity and want to estimate the chance that it will not rain at least one of the days. A coin was used to similate the weather each day. There was obtained 20 sets of three days (R for rain) means that there was a rain in the given day and (s for sunny means that there wasn't rain. Row one had 9 R and 11 S, row two has 11 R and 9 S, and row three has 11 R and 9 S. What is the experimental probability that it will not rain at least one of the three days? Answer by Theo(13342) (Show Source):
day sunny rain total p(rain)
1 11 9 20 9/20
2 9 11 20 11/20
3 9 11 20 11/20
the experimental probability that it will rain on all 3 days is 9/20 * 11/20 * 11/20 = .136125
the experimental probability that it will not rain on at least 1 of those days = 1 minus the probability that it will rain on all 3 of those days which is equal to 1 - .136125 = .863875.
my interpretation of this problem is that each day had 20 coin flips to determine the probability that it would be sunny on that day or rainy on that day.