Since the coeffcients are real, and 3+i is a solution, so is its
conjugate 3-i
Start with
x=-2, x=4, x=3+i, x=3-i
x+2=0, x-4=0, x-3-i=0 x-3+i=0
Multiply all the left sides and all the right sides, which gives
(x+2)(x-4)(x-3-i)(x-3+i) = 0
Do all that multiplying remembering that i2 = -1
and get
x4-8x3+14x2+28x-80 = 0
So the polynomial function f(x) is
f(x) = x4-8x3+14x2+28x-80
Edwin