SOLUTION: Factor: 5(m+3)^2 - 4(m+3)^3 Answer is supposed to be: -(m+3)^2(4m+7) This is from Section 0.6.2 Exercise no. 4, in open source book 'Chapter 0 - Prerequisites' available at http

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor: 5(m+3)^2 - 4(m+3)^3 Answer is supposed to be: -(m+3)^2(4m+7) This is from Section 0.6.2 Exercise no. 4, in open source book 'Chapter 0 - Prerequisites' available at http      Log On


   



Question 878902: Factor: 5(m+3)^2 - 4(m+3)^3
Answer is supposed to be: -(m+3)^2(4m+7)
This is from Section 0.6.2 Exercise no. 4, in open source book 'Chapter 0 - Prerequisites' available at http://www.stitz-zeager.com/index.html
Would appreciate any guidance someone could provide on how to get the answer.

Answer by KMST(5347) About Me  (Show Source):
You can put this solution on YOUR website!
The key is realizing that %28m%2B3%29%5E3=%28m%2B3%29%28m%2B3%29%5E2 , and then taking %28m%2B3%29%5E2 out as a common factor.
The rest is just understanding symbols and order of operations conventions in the language called "algebra".
5%28m%2B3%29%5E2+-+4%28m%2B3%29%5E3=+5%28m%2B3%29%5E2+-+4%28m%2B3%29%28m%2B3%29%5E2%22=+%5B%225-4%28m%2B3%29%22%5D%22+%28m%2B3%29%5E2=%0D%0A%285-4m-12%29%28m%2B3%29%5E2
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