SOLUTION: someone please show or explain the easiest way to understand this
Find the polynomial f(x) of degree 3 that has zeroes at 1,2, and 4 such that f(0) = -16.
Possible answers:
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Polynomials-and-rational-expressions
-> SOLUTION: someone please show or explain the easiest way to understand this
Find the polynomial f(x) of degree 3 that has zeroes at 1,2, and 4 such that f(0) = -16.
Possible answers:
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Question 71793: someone please show or explain the easiest way to understand this
Find the polynomial f(x) of degree 3 that has zeroes at 1,2, and 4 such that f(0) = -16.
Possible answers:
f(x) = x^3 -7x^2 +14x -16
f(x) = 2x^3 -14x^2 +28x -16
f(x) = 2x^3 -14x^2 +14x -16
f(x) = 2x^3 +7x^2 +14x +16
Thanks to anyone who can help me Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the polynomial f(x) of degree 3 that has zeroes at 1,2, and 4 such that f(0) = -16.
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f(x)= a(x-1)(x-2)(x-4)
Now find "a".
f(0)= a(0-1)(0-2)(0-4)=-16
a(-1)(-2)(-4)=-16
-8a=-16
a=2
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Therefore f(x)=2(x-1)(x-2)(x-4)
Cheers,
Stan H.
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