Question 663336: how do i figure this equation determine all integral values of k so that trinomials can be factored x^2+kx+10 Found 3 solutions by checkley79, Alan3354, ReadingBoosters:Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! x^2+kx+10
K=2+5=7 ANS.
(X+2)(X+5)
K=-5-2=-7 ANS.
(X-2)(X-5)
K=10+1=11 ANS.
(X+10)(X+1)
K=-10-1=-11 ANS.
(X-10)(X-1)
You can put this solution on YOUR website! how do i figure this equation determine all integral values of k so that trinomials can be factored x^2+kx+10
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k can be the sum of the factors of 10.
eg,
k = 1+10 = 11
k = -1-10 = -11
etc
Hint: there are 2 more
You can put this solution on YOUR website! x^2 + kx + 10
multiples of 10
1,10 where k would be 10+1 = 11
(x+1)(x+10) = x^2 + 10x + 1x + 10 = x^2 + 11x + 10
-1,-10 where k would be -10+-1=-11
(x-1)(x-10) = x^2 - 10x - 1x + 10 = x^2 - 11x + 10
2,5 where k would be 5+2 = 7
(x+2)(x+5) = x^2 + 2x + 5x + 10 = x^2 + 7x + 10
-2+-5 where k would be -5+-2=-7
(x-2)(x-5) = x^2 - 2x - 5x + 10 = x^2 - 7x + 10
k could equal -7, 7, -11 or 11
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