SOLUTION: C= nE/(R+nr) You are supposed to find n. Thanks, Danielle

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Question 57840: C= nE/(R+nr)
You are supposed to find n.
Thanks, Danielle

Found 2 solutions by funmath, phillv:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi Danielle,
C=nE%2F%28R%2Bnr%29; find n.
C%28R%2Bnr%29=nE%28R%2Bnr%29%2F%28R%2Bnr%29 Multiply both sides by the Denominator on the right.
CR%2BCnr=nE Distirbute the C.
CR%2BCnr-Cnr=nE-Cnr Get all the things with n's on one side of the = sign.
CR=n%28E-Cr%29 Factor out the n.
CR%2F%28E-Cr%29=n%28E-Cr%29%2F%28E-Cr%29 Divide both sides by (E-Cr)
CR%2F%28E-CR%29=n You're done!!!
highlight%28n=CR%2F%28E-CR%29%29 It's more traditional to have the variable on the left.
Happy Calculating, Danielle!!!

Answer by phillv(13) About Me  (Show Source):
You can put this solution on YOUR website!
C=nE/(R+nr)
Start by getting rid of the denominator and multiplying both sides of the equation by (R+nr) ie C(R+nr)= (nE(R+nr))/(R+nr)
cancell out the (R+nr) in both the numerator and denominator on the right side of the equation.
This leaves C(R+nr)=nE
now expand the expression on the left side in order to isolate terms involving n on the left side.
CR+Cnr=nE
Subtract Cnr from both sides of the equation in order to get all terms involving n on one side of the equation.
CR+Cnr-Cnr=nE-Cnr
CR=nE-Cnr
now factor out n from the right side of the equation
CR=n(E-Cr)
divide both sides of the equation by (E-Cr) in order to isolate n on one side of the equation.
CR/(E-Cr)=n(E-Cr)/(E-Cr)
cancell out (E-Cr) in the denominator and numerator on the right side.
this leaves CR/(E-Cr)=n or n=CR/(E-Cr)