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Hi,
x^3+8x^2+2x+16 Note: x = -8 is a root, thus(x+8) one factor
Applying synthetic division: (x^3+8x^2+2x+16)/(x+8) = x^2 + 2
-8 1 8 2 16
-8 0 -16
1 0 2 0
x^3+8x^2+2x+16 = (x+8)(x^2+2) = x^3 + 8x^2 + 2x + 16
F First terms x^3
O Outside terms 2x
I Inside term 8x^2
L Last terms 16
2bc+4b-5c-10 = 2b(c + 2) - 5(c + 2 = (2b-5)(c+2)
F First terms 2bc
O Outside terms 4b
I Inside term -5c
L Last terms -10