SOLUTION: Factor completely. 20w^2+100wg+125g^2 All of the examples I have offer numbers that have square roots so i'm not sure how to solve this one. Any help you can give is very much

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor completely. 20w^2+100wg+125g^2 All of the examples I have offer numbers that have square roots so i'm not sure how to solve this one. Any help you can give is very much       Log On


   



Question 352211: Factor completely.
20w^2+100wg+125g^2
All of the examples I have offer numbers that have square roots so i'm not sure how to solve this one. Any help you can give is very much appreciated.
Thank you in advance!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

20w%5E2%2B100wg%2B125g%5E2 Start with the given expression


5%284w%5E2%2B20wg%2B25g%5E2%29 Factor out the GCF 5


Now let's focus on the inner expression 4w%5E2%2B20wg%2B25g%5E2




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Looking at 4w%5E2%2B20wg%2B25g%5E2 we can see that the first term is 4w%5E2 and the last term is 25g%5E2 where the coefficients are 4 and 25 respectively.

Now multiply the first coefficient 4 and the last coefficient 25 to get 100. Now what two numbers multiply to 100 and add to the middle coefficient 20? Let's list all of the factors of 100:



Factors of 100:
1,2,4,5,10,20,25,50

-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 100
1*100
2*50
4*25
5*20
10*10
(-1)*(-100)
(-2)*(-50)
(-4)*(-25)
(-5)*(-20)
(-10)*(-10)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 20? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 20

First NumberSecond NumberSum
11001+100=101
2502+50=52
4254+25=29
5205+20=25
101010+10=20
-1-100-1+(-100)=-101
-2-50-2+(-50)=-52
-4-25-4+(-25)=-29
-5-20-5+(-20)=-25
-10-10-10+(-10)=-20



From this list we can see that 10 and 10 add up to 20 and multiply to 100


Now looking at the expression 4w%5E2%2B20wg%2B25g%5E2, replace 20wg with 10wg%2B10wg (notice 10wg%2B10wg adds up to 20wg. So it is equivalent to 20wg)

4w%5E2%2Bhighlight%2810wg%2B10wg%29%2B25g%5E2


Now let's factor 4w%5E2%2B10wg%2B10wg%2B25g%5E2 by grouping:


%284w%5E2%2B10wg%29%2B%2810wg%2B25g%5E2%29 Group like terms


2w%282w%2B5g%29%2B5g%282w%2B5g%29 Factor out the GCF of 2w out of the first group. Factor out the GCF of 5g out of the second group


%282w%2B5g%29%282w%2B5g%29 Since we have a common term of 2w%2B5g, we can combine like terms

So 4w%5E2%2B10wg%2B10wg%2B25g%5E2 factors to %282w%2B5g%29%282w%2B5g%29


So this also means that 4w%5E2%2B20wg%2B25g%5E2 factors to %282w%2B5g%29%282w%2B5g%29 (since 4w%5E2%2B20wg%2B25g%5E2 is equivalent to 4w%5E2%2B10wg%2B10wg%2B25g%5E2)


note: %282w%2B5g%29%282w%2B5g%29 is equivalent to %282w%2B5g%29%5E2 since the term 2w%2B5g occurs twice. So 4w%5E2%2B20wg%2B25g%5E2 also factors to %282w%2B5g%29%5E2



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So our expression goes from 5%284w%5E2%2B20wg%2B25g%5E2%29 and factors further to 5%282w%2B5g%29%5E2


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Answer:

So 20w%5E2%2B100wg%2B125g%5E2 factors to 5%282w%2B5g%29%5E2