Question 33471: 2(3x2+X+2)
Answer by mszlmb(115)   (Show Source):
You can put this solution on YOUR website! check 4 problems on my part
is this even ur equation?? 
if its not then repost or sumthin cuz that's what im solving :oD
let's solve by factoring.
A=3, B=1, C=2. (because the linear formula is  )
yea, we R gonna ignore the 2 in front 4 now.
now we do A*C. 3*2 is 6. now we need find 2 numbers that multiply 2 6 and add to B, 1. simply enough, our numbers are -2 and 3. but we have a problem. -2 and 3 don't multiply to 6, they multiply to negative 6. we're going to do this:
is our equation.  is the same thing, let's disregard the 4 for now. let's focus on  . it's the same as saying  , is it not (yea, it is).. ok so now we look for things we can factor.  have a similarity: 3x. So we're going to factor the 3x out. It thence becomes 3x(x+1). now we factor -2x-2. Take a wild guess.. YES! The common factor is -2! we factor -2x-2 to obtain -2(x+1).
ok so  is the same as 3x(x+1)-2(x+1) . Now put the x+1's together and what's left? 3x-2. You have factored into
(3x-2)(x+1). Let's see the entire equation.
 how do we take that annoying +4 out of there? well it would be 8 outside the parenthises, wouldn't it? (because 2(4)=8).
our equation is upgraded to 2(3x-2)(x+1)+8.
Now we have a split; either your equation is f(x)=2(3x-2)(x+1)+8 , or 0=2(3x-2)(x+1)+8.
f(x)=2(3x-2)(x+1)+8:
There are an infinite amount of answers, I'm quite certain, because you are naming a function: an entire infinite graph.
0=2(3x-2)(x+1)+8
This is simpler, and has an answer. We begin with
0=2(3x-2)(x+1)+8
-8=2(3x-2)(x+1)
-4=(3x-2)(x+1)
0=(3x-2)(x+1)+4
this turns out yet another parabola:
I'm sorry if I'm not more help. If you find that I'm wrong please tell me so I can learn this. THNX!
ps I really recommend talking 2 ur teacher about this as it is hard to explain without pen and paper.
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