SOLUTION: On this problem: 20/(a^2+a-6) + 6/(a+3) = 5/(a-2) solve for a, I had help with this: 6a + 8 = 5a + 15 (please explain how this section came about. I am still not sure

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: On this problem: 20/(a^2+a-6) + 6/(a+3) = 5/(a-2) solve for a, I had help with this: 6a + 8 = 5a + 15 (please explain how this section came about. I am still not sure       Log On


   

Question 319345: On this problem: 20/(a^2+a-6) + 6/(a+3) = 5/(a-2) solve for a, I had help with this:


6a + 8 = 5a + 15 (please explain how this section came about. I am still not sure how to explain it. Thank you).
6a + 8 - 5a = 15
a + 8 = 15
a = 8 +15
a = 7

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You need to find a common denominator.
a%5E2%2Ba-6=%28a%2B3%29%28a-2%29
Use %28a%2B3%29%28a-2%29 as the common denominator.


%2820%2B%286%28a-2%29%29-5%28a%2B3%29%29%2F%28%28a-2%29%28a%2B3%29%29=0
If the fraction equals zero, then the numerator must equal zero.
20%2B6a-12-5a-15=0<---- This is the same as your first line except 5a+15 is on the right.
-7%2Ba=0
a=7
highlight%28a=7%29