SOLUTION: I have 2 problems I need help with please. The first is: 8/y-1/3=5y solve for y. I came up with y=9. Is this correct? The second problem I do not understand. 20/(a^2+a-6) + 6/(a+3)
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-> SOLUTION: I have 2 problems I need help with please. The first is: 8/y-1/3=5y solve for y. I came up with y=9. Is this correct? The second problem I do not understand. 20/(a^2+a-6) + 6/(a+3)
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Question 318849: I have 2 problems I need help with please. The first is: 8/y-1/3=5y solve for y. I came up with y=9. Is this correct? The second problem I do not understand. 20/(a^2+a-6) + 6/(a+3) = 5/(a-2) solve for a. Please advise. Thank you. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! I'm assuming this is the problem?
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Plug the solution into the original equation to verify.
False, so cannot be the solution.
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Multiply both sides by to get rid of fractions.
Use the quadratic formula,
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Multiply both sides by