Given that 5 is one of the zeros for R(x) = x^3 -11x^2 + 37x-35, Find the other zeros.. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Given that 5 is one of the zeros for R(x) = x^3 -11x^2 + 37x-35, Find the other zeros..
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5)....1....-11....37....-35
.......1......-6....7...|..0
Quotient: x^2 -6x + 7
Zeroes:
x = [6 +- sqrt(36 - 4*1*7)]/2
x = [6 +- sqrt(8)]/2
x = [3 +- sqrt(2)]
x = 3 + sqrt(2) or x = 3-sqrt(2)
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Cheers,
Stan H.