Question 174085: how do you solve b/b-1+2b/b^2-1
Answer by nycsub_teacher(90)   (Show Source):
You can put this solution on YOUR website! [b/(b - 1)] + [2b/(b^2 - 1)]
Look for LCD/
The LCD is b^2 - 1.
Divide the LCD by each denominator and then multiply the quotient by each numerator.
b^2 - 1 divided by b - 1 = b + 1
b^2 - 1 divided by itself = 1
We now have this:
[b(b + 1) + 2b(1)]/(b^2 - 1)
(b^2 + 3b)/(b^2 - 1)
The denominator is the difference of two perfect squares.
So, factor the denominator.
Final answer:
(b^2 + 3b)/(b - 1)(b + 1)
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