SOLUTION: find the heigth of the track if x=50 f=(x)=0.004x^3-0.2x^2+5.2x+6

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: find the heigth of the track if x=50 f=(x)=0.004x^3-0.2x^2+5.2x+6      Log On


   

Question 167702: find the heigth of the track if x=50

f=(x)=0.004x^3-0.2x^2+5.2x+6
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=0.004x%5E3-0.2x%5E2%2B5.2x%2B6 Start with the given function.


f%2850%29=0.004%2850%29%5E3-0.2%2850%29%5E2%2B5.2%2850%29%2B6 Plug in x=50.


f%2850%29=0.004%28125000%29-0.2%2850%29%5E2%2B5.2%2850%29%2B6 Cube 50 to get 125000.


f%2850%29=0.004%28125000%29-0.2%282500%29%2B5.2%2850%29%2B6 Square 50 to get 2500.


f%2850%29=500-500%2B260%2B6 Multiply


f%2850%29=266 Combine like terms.


So at x=50, the height of the track is 266 units (replace this with the given units ie feet or meters)