SOLUTION: is it possible to draw a polygon that has interior angles that sum up to 1300

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Question 905815: is it possible to draw a polygon that has interior angles that sum up to 1300

Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The interior angles of any polygon always add up to a constant value, which depends only on the number of sides.
The sum of the interior angles of a polygon is given by the formula :
sum=180%28n-2%29 degrees where n is the number of sides
you are given +sum=1300
so, plug it is sum=180%28n-2%29
1300=180%28n-2%29 ...solve for n
1300%2F180=n-2
7.22=n-2
7.22%2B2=n
9.22=n
since the number of the sides is decimal number, answer is: it is not possible to draw a polygon that has interior angles that sum up to 1300

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
No, the sum is always an integral multiple of 180 degrees.
If n = # of angles (also the # of sides),
Sum = (n-2)*180, n = 3,4,5 ...
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The minimum value of n = 3. No polygon has fewer than 3 sides.
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Don't try the old joke, "How many sides does a circle have?" Answer: 2, inside and outside.