SOLUTION: The sum of the interior angles of a polygon is 8y. If Y is 15 greater than the number of sides of the polygon, how many sides does the polygon have?

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Question 522948: The sum of the interior angles of a polygon is 8y. If Y is 15 greater than the number of sides of the polygon, how many sides does the polygon have?
Answer by stanbon(75887) (Show Source):
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The sum of the interior angles of a polygon is 8y. If Y is 15 greater than the number of sides of the polygon, how many sides does the polygon have?
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Let number of sides be "n":
sum of interior angles = (n-2)180 = 8Y
y = n+15
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Substitute for "y" and solve for "n"
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(n-2)180 = 8(n+15)
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(n-2)180 = 8n+120
180n-360 = 8n+120
172n = 480
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That does not turn out to be a whole number.
Please check the wording of your problem.
I have some suspicion about that "8Y".
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Cheers,
Stan H.
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