SOLUTION: a survey indicates that 30% of students play football, 60% play basketball, and 10% play both. If a student is picked at random, the ODDS that he plays either football or basketbal

Algebra ->  Permutations -> SOLUTION: a survey indicates that 30% of students play football, 60% play basketball, and 10% play both. If a student is picked at random, the ODDS that he plays either football or basketbal      Log On


   

Question 473849: a survey indicates that 30% of students play football, 60% play basketball, and 10% play both. If a student is picked at random, the ODDS that he plays either football or basketball but not both is
a. 9 to 1
b. 4 to 1
c. 7 to 3 d. 3 to 2 or e. fifty-fifty
can you explain the method of solving it, Does that make sence?
Found 3 solutions by robertb, ashleighb84, richwmiller:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The problem needs restatement: there is something wrong with the phrase " 30% of students play football, 6% play basketball, and 10% play both"

Answer by ashleighb84(7) About Me  (Show Source):
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
let's say there are 100 students
30 play foot
60 play basket
10 play both
so
20 play just foot
50 play just basket
so out of 100, 70 play either one but not both.
70/100= 7